# -*- coding: utf-8 -*-def Num2MoneyFormat( change_number ):    """    .转换数字为大写货币格式( format_word.__len__() - 3 + 2位小数 )    change_number 支持 float, int, long, string    """    format_word = ["分", "角", "元",               "拾","百","千","万",               "拾","百","千","亿",               "拾","百","千","万",               "拾","百","千","兆"]    format_num = ["零","壹","贰","叁","肆","伍","陆","柒","捌","玖"]    if type( change_number ) == str:        # - 如果是字符串,先尝试转换成float或int.        if '.' in change_number:            try:    change_number = float( change_number )            except: raise ValueError, '%s   can\'t change'%change_number        else:            try:    change_number = int( change_number )            except: raise ValueError, '%s   can\'t change'%change_number    if type( change_number ) == float:        real_numbers = []        for i in range( len( format_word ) - 3, -3, -1 ):            if change_number >= 10 ** i or i < 1:                real_numbers.append( int( round( change_number/( 10**i ), 2)%10 ) )    elif isinstance( change_number, (int, long) ):        real_numbers = [ int( i ) for i in str( change_number ) + '00' ]    else:        raise ValueError, '%s   can\'t change'%change_number    zflag = 0                       #标记连续0次数，以删除万字，或适时插入零字    start = len(real_numbers) - 3    change_words = []    for i in range(start, -3, -1):  #使i对应实际位数，负数为角分        if 0 <> real_numbers[start-i] or len(change_words) == 0:            if zflag:                change_words.append(format_num[0])                zflag = 0            change_words.append( format_num[ real_numbers[ start - i ] ] )            change_words.append(format_word[i+2])        elif 0 == i or (0 == i%4 and zflag < 3):    #控制 万/元            change_words.append(format_word[i+2])            zflag = 0        else:            zflag += 1    if change_words[-1] not in ( format_word[0], format_word[1]):        # - 最后两位非"角,分"则补"整"        change_words.append("整")    return ''.join(change_words)print Num2MoneyFormat( 343.45 )

运行结果：叁百肆拾叁元肆角伍分